29. Homogeneous variable

Another method for the solution of non-homogeneous, linear equations involves the introduction of homogenous variables. In (26.1), set

x1 = t1/t1n+1, x2 = t2/t1n+1, ··· , x1 = tn/t1n+1

and multiply by t1n+1. Then (26.1) becomes the homogeneous system

a11t1 + ··· + a1ntn - c1tn+1 = 0,
····························································(29.1)
ap1t1 + ··· + apntn - cptn+1 = 0.

Every solution of (29.1) in which tn+1 0 yields a solution of (26.1). However, you must find out whether (29.1) has solutions with tn+1 0.

According to Theorem 14, the number of linearly independent solutions of (29.1) is n + 1 - r1. According to the same Theorem,

a11t1 + ··· + a1ntn = 0,
····························································(29.2)
ap1t1 + ··· + apntn = 0

has exactly n - r linearly independent solutions. Every solution of (29.1) with tn+1=0 yields a solution of (29.2) and every solution of (29.2) a solution of (29.1) with tn+1 = 0, whence (29.1) has exactly then solutions with tn+1 0, if

n + 1 - r1 > n - r

or r1 < r + 1. On the other hand, certainly r1 = r or r1 = r + 1, so that is r1<r+ 1 is equivalent to r1 = r. Hence you have arrived again at the statement of Theorem 15.

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