36. Hadamard's determinant estimate
In Section 25, it has been shown that, if a1, ··· , an are linearly independent (n,1)-vectors, numbers b11, ··· bnn can be chosen so that
c1
= b11a1,
c2 = b21c1
+ b22a2,
c3 = b31c1
+ b32a2 + b33a3,
················································
cn = bn1c1
+ bn2a2 + ···
+ bnnan
form a normalized
orthogonal system. Due to the linear independence of the c1,···,
cn, all the bii
0,
so that you can solve the system of equation for the ai
and obtain
a1
= p11c1,
a2 = p12c1
+ p22c2,
····························································
(36.1)
an = p1nc1
+ p2nc2 + ···
+ pnncn
These equations can be represented by a single matrix equation. Treat the a1,···,an as the columns of a matrix A, the c1,···, cn as the columns of an unitary matrix C and set

(36.1) can now be written in the form A = CP, whence
![]()
Since
is again
unitary, you find: Every regular matrix A can be
converted into a triangular matrix by multiplication from the
left by a unitary matrix. Taking on both sides the absolute
values of the determinants and taking into consideration that ||
|| = 1,
you find
![]()
Let now all the vectors a1,···,an be normalized:
![]()
Since the ci, are orthogonal to each other and normalized, (36.1) yields
![]()
Hence |pii|
1. Since ||P|| = |p11···pnn||
1, (36.3) yields
||A||
1
(36.5)
The equality sign only occurs when
all |pii| = 1. However, by
(36.4), all pik with
i
k vanish, so that P becomes a diagonal
matrix. Moreover, this means that
ai = piici with |pii| = 1 (i = 1, ··· , n),
so that the ai themselves are mutually orthogonal. Hence follows:
If A is a
matrix, the columns of which form a system of orthogonalized
vectors, then always ||A||
1 and the equality sign
only occurs if A is a unitary matrix.
The inequality ||A||
1
also applies trivially if the columns of A are linearly
dependent, since then |A| = 0.
If we now multiply the columns of A in sequence by the positive numbers a1,···,an, the determinant |A| is multiplied by the product a1···an and you have for the norms of the columns
![]()
The inequality (36.5) now yields:
Provided (36.6) applies, there applies Hadamard's estimate
||A||
a1···an.
The equality sign only arises when the columns of A are mutually orthogonal. A corresponding estimate arises with regard to the norms of the rows. *
* As Analytic Geometry shows, this statement is the n-dimensional analogue to the rules that of all parallelograms with given side lengths a1, a2 the rectangle has the largest area and that of all parallelepipeds with given edge lengths a1, a2, a3 the cube has the largest volume.